60=16t^2+(-55)t+60=0

Solution for 60=16t^2+(-55)t+60=0 equation:

60=16t^2+(-55)t+60=0

We move all terms to the left:

60-(16t^2+(-55)t+60)=0


We calculate terms in parentheses: -(16t^2+(-55)t+60), so:

16t^2+(-55)t+60

We multiply parentheses

16t^2-55t+60

Back to the equation:

-(16t^2-55t+60)


We get rid of parentheses

-16t^2+55t-60+60=0

We add all the numbers together, and all the variables

-16t^2+55t=0

a = -16; b = 55; c = 0;
Δ = b2-4ac
Δ = 552-4·(-16)·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-55}{2*-16}=\frac{-110}{-32}
=3+7/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+55}{2*-16}=\frac{0}{-32}
=0
$